Bourbaki

Exercise 11, § 2

Lie Groups and Lie Algebras, II

Bourbaki marks this one as harder than the rest.

Let Y and Z be two disjoint sets (Y being endowed with a total order structure), let X=Y∪ZX = Y \cup Z and let l=L(X)l = L(X). Let αY\alpha_Y be the submodule of ll generated by Z and [l,l][l, l]; it is an ideal of the Lie algebra ll. We shall make explicit a basic family of αY\alpha_Y.

Let M be the set of positive integer-valued functions on Y, with finite support. If m∈Mm \in M, we denote by θm\theta^m the endomorphism of ll given by

θm=∏y∈Y(ad⁡y)m(y), \theta^m = \prod_{y \in Y} (\operatorname{ad} y)^{m(y)},
the product being relative to the order relation given on Y. We denote by SS the subset of Y×MY \times M formed by the pairs (u,m)(u, m) such that there exists y∈Yy \in Y for which y>uy > u and m(y)≥1m(y) \geq 1. Prove that the elements
θm(u) for (u,m)∈S and θm(z) for (z,m)∈Z×M \theta^m(u) \text{ for } (u, m) \in S \quad \text{ and } \quad \theta^m(z) \text{ for } (z, m) \in Z \times M
form a basic family of the Lie algebra αY\alpha_Y.

(Reduce to the case where Y is finite, and reason by induction on Card(Y). Use the cor. of prop. 10, applied to the greatest element yy of Y, and apply the induction hypothesis to Y−{y}Y - \{y\}.)

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.