Bourbaki

Exercise 5, § 6

Lie Groups and Lie Algebras, II

Let gg be a nilpotent Q\mathbf{Q}-Lie algebra, which is provided with the Hausdorff group law, denoted (x,y)↦x.y(x, y) \mapsto x . y. (a) Prove that, if x∈gx \in g, y∈gy \in g, one has

x.y.x−1=∑n=081n!(ad x)n(y). x . y . x^{-1} = \sum_{n=0}^8 \frac{1}{n!} (\mathrm{ad}\ x)^n(y).
(Use Exercise 2.)

(b) Let h\mathfrak{h} be a subset of gg. Prove that h\mathfrak{h} is a Lie subalgebra (resp. an ideal) of gg if and only if it is a saturated subgroup (resp. a saturated distinguished subgroup) of the group gg. (Use the formulas of Exercise 4 d) to pass from the group law to that of the Lie algebra.) (c) Let h\mathfrak{h} be a subgroup of the group gg. Prove that the P\mathbf{P}-saturation of h\mathfrak{h} is Q.h\mathbf{Q}.\mathfrak{h}. (d) Let h\mathfrak{h} be a Lie subalgebra of gg. Prove that the centralizer (resp. the normalizer) of h\mathfrak{h} in the group gg is the set of the x∈gx \in g such that (ad x)(h)=0(\mathrm{ad}\,x)(\mathfrak{h}) = 0 (resp. such that (ad x)(h)⊂h(\mathrm{ad}\,x)(\mathfrak{h}) \subset \mathfrak{h}). (e) Prove that the descending central sequence of the Lie algebra gg coincides with that of the group gg and that the associated graded Lie algebra gr(g)\mathrm{gr}(g) is the same from the point of view of “group” and from the point of view of “Lie algebra”.

Solution

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