Exercise 1, § 4

Consider the covering $(E, p)$ introduced in Exercise 4 of I, p. 148. Prove that it is not Galoisian, but that the subgroup $p_*(\pi_1(E, x))$ of $\pi_1(B, b)$ is distinguished. This provides a counter-example to the converse of Theorem 1 (III, p. 305).