§ 4. Homotopy and coverings
1. Homotopy and coverings
Proposition 1 01Z5
Let B be a topological space and let E be a covering of B. Let be a topological space and let and be continuous mappings of into B. If the mappings and are homotopic, the coverings and of are isomorphic.
Let be a homotopy joining to . Let us denote by and the mappings and of into . If , we have and the coverings and of are therefore isomorphic (I, p. 15). Since the topological space is locally connected and simply connected (I, p. 127, corollary), the coverings and of are isomorphic (I, p. 130, cor. 1 of prop. 8).
Corollary 01Z6
A topological space homotopic to a simply connected topological space is simply connected.
Let B and be topological spaces, let be a homotopy equivalence and let be a continuous mapping, inverse to up to homotopy. Let E be a covering of B. Since is homotopic to the identity mapping of B, the covering E is isomorphic to the covering (prop. 1). If the space is simply connected, the covering is trivializable. Consequently, the covering E is trivializable. This proves that the space B is simply connected.
Remark 01Z7
Let G be a discrete topological group. With the notation of the proposition, suppose that E is a principal covering with group G. Then the coverings and are isomorphic principal coverings (I, p. 131, remark).
Proposition 2 (Lifting of homotopies) 01Z8
Let B be a topological space and let E be a covering of B. Let be a topological space and let and be continuous mappings of into B. Let be a homotopy joining to . Let be a continuous lifting of to E. There exists a unique continuous mapping E lifting which is a homotopy with initial term . Its term is a continuous lifting of to E.
This follows from corollary 3 of prop. 8 of I, p. 130, applied to the simply connected and locally connected topological space .
2. Lifting of paths
Proposition 3 01Z9
Let B be a topological space and let be a covering. Let us denote by the mapping . Let us denote by ( resp. ) the mapping defined by . Then, the diagram
E
B is a cartesian square.
The topological space is locally connected, locally compact and simply connected. The proposition thus follows from prop. 9 of I, p. 131, applied with and .
Corollary 1 01ZA
The mapping is a covering.
This follows from I, p. 71, cor. 2 of prop. 1.
Corollary 2 (Lifting of paths) 01ZB
Let be a covering, let be a point of E and . The mapping is a homeomorphism of the space of paths in E with origin onto the space of paths in B with origin .
With the notation of proposition 3, we have and . The corollary then follows from I, p. 10, cor. of prop. 4.
We shall say that a continuous mapping satisfies the path-lifting property if, for every path B and every point of E lying over , there exists a path in E with origin which lifts . Such a path is then unique if is étale and separated (I, p. 34, cor. 1 of prop. 11). Let E be a covering and its projection; the mapping is étale, separated and has the path-lifting property (corollary 2). For a partial converse, cf. III, p. 315, corollary.
Proposition 4 01ZC
Let be an étale and separated mapping which satisfies the path-lifting property. Let and be points of B and let be a point of E such that . Let and be two strictly homotopic paths joining to in B. The paths with origin in E which lift respectively and have the same term and are strictly homotopic.
Let B be a strict homotopy joining to . For , let be the unique path with origin in E which lifts the path . For , put ; we have . The mapping is constant on ; by construction, it is continuous on for every . It is therefore continuous, by I, p. 37, cor. 1 of th. 1. In particular, the mapping from into defined by is a continuous lifting of the constant path with image ; it is therefore constant. This proves that the mapping is a strict homotopy joining to .
Corollary 1 01ZD
Let B be a topological space and let E be a covering of B; let us denote by its projection. For every pair of points of E, the mapping is injective. In particular, for every point of E, the homomorphism is injective.
Corollary 2 01ZE
Let B be a topological space and let E be a covering of B; let us denote by its projection. Let be a point of E, and put . In order that the class in of a loop in B at should belong to the image subgroup of the homomorphism , it is necessary and sufficient that the path with origin lifting should be a loop of E at .
The condition is obviously sufficient. Conversely, let be a loop of E at . Put and suppose that the loops and are strictly homotopic. By Prop. 4, the path has the same end point as the path . It is therefore a loop at .
Corollary 3 01ZF
Let B be a topological space and let and be coverings of B. Let us denote by their fibre product over B, and let be a point of E. The image of the homomorphism is the intersection of the images of the homomorphisms and .
Let be a loop in B at and, for , let be the path with origin in lifting . The fibre product over B is a covering of B (I, p. 72, cor. 3 of Prop. 2), and the path is the unique path with origin in E which lifts . In order that should be a loop, it is necessary and sufficient that and should be so. Corollary 3 thus follows from Corollary 2.
3. Operations of the Poincaré groupoid in coverings
Let B be a topological space and let B be an etale and separated mapping satisfying the path-lifting property (III, p. 302); this is the case if the mapping makes E a covering of B (loc. cit.). Let and be points of B and let be a path in B joining to . For every point of the fibre , let us denote by the term of the path with origin in E which lifts . The point belongs to the fibre and depends only on the class of the path III, p. 302, prop. 4); we shall thus write instead of .
If is the constant path at , one has because the constant path with origin lifts .
Let be another point of B and let . For every point of , one has:
In fact, let denote the lift of with origin and the lift of with origin . The paths and can be juxtaposed and is the path with origin lifting .
Let us denote by the mapping such that, for and , one has
For every and every , it follows from relation (1) that one has
The family therefore defines a law of right operation of the groupoid on the set E relative to the mapping B (II, p. 167). It is called the canonical operation of the groupoid associated with the mapping . The mapping defines a law of right operation of the group on the fibre of E. This operation is called the canonical operation of on the fibre .
Remark 01ZG
Let and be two points of B a point of a path in B and the path in E originating at which lifts . For every , let us denote by the path ; the path in E originating at which lifts is the path whose term is the point . We have therefore for every .
Let be a topological space and let be an étale and separated mapping satisfying the path lifting property. Let and be continuous mappings such that . For and , we have:
In fact, let be a path in B whose strict homotopy class is , and let us denote by the path in E originating at which lifts ; the path is then the lift originating at of in .
In particular, for and Id, we have
Let and be étale and separated mappings satisfying the path lifting property. Let be a point of B. If is a B-morphism, the mapping is a -morphism.
Theorem 1 01ZH
Let B be a topological space, let be a covering of B, let be a point of B and let be a point of the fibre .
a) The orbit of for the canonical operation of the group is the intersection of and the arcwise connected component of in E. In particular, if the space E is arcwise connected, this operation is transitive.
b) The stabilizer (A, I, p. 51) of is the subgroup of .
c) For every , we have Int( ) .
d) If the space B is connected and the covering E is Galois, the subgroup is normal in .
Assertion a) is immediate. Assertion b) follows from Cor. 2 of Prop. 4 (III, p. 303). Assertion c) follows from b) and from Proposition 2 of A, I, p. 52. Finally, suppose that B is connected and that E is a Galois covering of B. For every , there exists a B-automorphism of E such that I, p. 102, th. 2, c)). We have , whence . Assertion d) therefore follows from c).
4. Case of coverings associated with a principal covering
Let B be a topological space, let G be a discrete topological group, and let E be a principal covering of B with group G. Let us denote by the projection of the B-space E. Let be a point of B and let be a point of .
Proposition 5 01ZI
The mapping of into G which, to , associates the unique element of G such that , is a group homomorphism, whose kernel is the subgroup of . If E is connected, this homomorphism is surjective.
For every , one has Int().
Let E be a principal covering of B with group G, let be a point of , and let us denote by the projection of E. For every , the mapping is a B-automorphism of E. Hence, for every , every , and every , one has the relation cf. III, p. 305, relation (4)). Consequently, for , one has
which proves that is a group homomorphism.
Its kernel is the stabilizer of for the canonical operation of , hence is equal to by Theorem 1 of III, p. 305. The mapping is a bijection of G onto . The image of the homomorphism is therefore the set of such that belongs to the orbit of for this operation. If E is connected, operates transitively on loc. cit.) and the homomorphism is surjective.
Let ; for every , one has
whence . This completes the proof of the proposition.
Example 1 01ZJ
Let F be a discrete set endowed with an operation of G, and let be the associated covering of B. Let us denote by the canonical B-morphism. It is a morphism of coverings. For every and every , one then has
(5)
If one identifies F with by the bijective mapping , it follows that the right operation Aut(X) is the composite of the homomorphism , the antihomomorphism of G into itself and the homomorphism Aut(F) deduced from the operation of G on F.
Example 2 01ZK
Let H be a discrete topological group, let be a group morphism. Endow H with the left operation of G given by , for and . Let be the associated covering; it is a principal covering of group H (I, p. 107, Example 6). Let us denote by the canonical mapping and put . We have .
In fact, let be a loop at in B, let be its class in and let ; one has therefore . Let be a path with origin in E; then is a path with origin in which lifts the path in B, so that
which proves that .
Exercises
See the exercises for § 4.