Bourbaki

Proposition 4

Tag 01ZC, permanent. Cite it as [Bourbaki, Tag 01ZC].

Topologie algébrique, chapter III, § 4. Homotopie et revêtements

Let p:E→Bp: E\rightarrow B be an étale and separated mapping which satisfies the path-lifting property. Let aa and bb be points of B and let xx be a point of E such that p(x)=ap(x) =a. Let c0c_0 and c1c_1 be two strictly homotopic paths joining aa to bb in B. The paths with origin xx in E which lift respectively c0c_0 and c1c_1 have the same term and are strictly homotopic.

Let σ:I×I→\sigma :\mathbf{I}\times \mathbf{I}\rightarrow B be a strict homotopy joining c0c_0 to c1c_1. For s∈Is\in \mathbf{I}, let cs′c'_s be the unique path with origin xx in E which lifts the path t↦σ(t,s)t\mapsto \sigma (t, s). For (t,s)∈I×I(t, s)\in \mathbf{I}\times \mathbf{I}, put σ′(t,s)=cs′(t)\sigma '(t, s) =c'_s(t); we have p∘σ′=σp\circ \sigma '=\sigma. The mapping σ′\sigma ' is constant on {0}×I\{0\} \times \mathbf{I}; by construction, it is continuous on I×{s}\mathbf{I}\times \{s\} for every s∈Is\in \mathbf{I}. It is therefore continuous, by I, p. 37, cor. 1 of th. 1. In particular, the mapping from I\mathbf{I} into EbE_b defined by s↦σ′(1,s)s\mapsto \sigma '(1, s) is a continuous lifting of the constant path with image bb; it is therefore constant. This proves that the mapping σ′\sigma ' is a strict homotopy joining c0′c'_0 to c1′c'_1.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.