Bourbaki

Example 1

Tag 01ZJ, permanent. Cite it as [Bourbaki, Tag 01ZJ].

Topologie algébrique, chapter III, § 4. Homotopie et revêtements

Let F be a discrete set endowed with an operation of G, and let X=E×GFX = E\times^GF be the associated covering of B. Let us denote by φ:E×F→X\varphi : E\times F\rightarrow X the canonical B-morphism. It is a morphism of coverings. For every γ∈π1(B,b)\gamma \in \pi_1(B, b) and every f∈Ff\in F, one then has

(5)

φ(x,f)⋅γ=φ(x⋅γ,f)=φ(x⋅h(E,x)(γ)−1,f)=φ(x,h(E,x)(γ−1)⋅f) \varphi (x, f)\cdot \gamma =\varphi (x\cdot \gamma , f) =\varphi (x\cdot h_{(E,x)}(\gamma )^{-1}, f) =\varphi (x, h_{(E,x)}(\gamma^{-1})\cdot f)

If one identifies F with XbX_b by the bijective mapping f↦φ(x,f)f\mapsto \varphi (x, f), it follows that the right operation π1(B,b)→\pi_1(B, b)\rightarrow Aut(Xb_b)∘^{\circ} is the composite of the homomorphism h(E,x)h_{(E,x)}, the antihomomorphism g↦g−1g\mapsto g^{-1} of G into itself and the homomorphism G→G\rightarrow Aut(F) deduced from the operation of G on F.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.