Bourbaki

Exercise 3, § 2

Tag 040A, permanent. Cite it as [Bourbaki, Tag 040A].

Algebraic Topology, IV, p. 457

[^1] Let X be a topological space and let xx be a point of X.

Let G be a group and let φ:π1(X,x)→G\varphi :\pi_1(X, x)\rightarrow G be a group homomorphism. Let (Un)n∈N(U_n)_{n\in\mathbf{N}} be a decreasing sequence of subspaces of X whose intersection is reduced to the point xx. For every nn, let GnG_n be the set of elements of G which are images by φ\varphi of the class of a loop contained in UnU_n. a) If G is countable, the sequence (Gn)(G_n) is stationary. (Reduce to the case where (Gn:Gn+1)⩾n+1(G_n: G_{n+1})\geqslant n+ 1 for every nn and consider an enumeration (γn)n(\gamma_n)_n of G; construct by induction elements λn∈Gn\lambda_n\in G_n such that, denoting wn=λ1...λnw_n=\lambda_1. . . \lambda_n, one has γi∉wnGn+1\gamma_i\notin w_nG_{n+1} for 1⩽i⩽n1\leqslant i\leqslant n. Now prove that the intersection ⋂iwiGi+1\bigcap_iw_iG_{i+1} is not empty.)

b) Suppose that G is abelian and that its identity element is the only indefinitely divisible element of G. Then ⋂nGn\bigcap_nG_n is reduced to the identity element. (Let aa be an element of the intersection; for every nn, let γn∈π1(Un,x)\gamma_n\in \pi_1(U_n, x) whose image by φ\varphi is equal to aa. Construct by induction path classes λn∈π1(Un,x)\lambda_n\in \pi_1(U_n, x) such that λn=γnλn+1d\lambda_n=\gamma_n\lambda^d_{n+1}, where dd is a fixed integer ⩾2\geqslant 2. Now prove that b=(d−1)φ(λ1)+ab= (d-1)\varphi (\lambda_1) +a is indefinitely divisible. Deduce that a=0a= 0.) c) More generally, if G is abelian and if every indefinitely divisible element of G is torsion, then the intersection of the GnG_n is formed of torsion elements.

[^1]: The results of this exercise and of the following one are taken from the article by J. W. Cannon and G. R. Conner, « On the fundamental groups of one-dimensional spaces », Topology and its Applications 153 (2006), p. 2648–2672.

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.