Bourbaki

Exercise 31, § 5

Tag 041O, permanent. Cite it as [Bourbaki, Tag 041O].

Algebraic Topology, IV, p. 475

Let f=(f1,...,fn):I→Rnf= (f_1, . . . , f_n):\mathbf{I}\rightarrow \mathbf{R}^n be a mapping of class C1C^1 such that f′(t)=0̸f'(t)= 0\not for all t∈It\in \mathbf{I}.

(a) Assume that f1′(t)>0f'_1(t)>0 for all t∈It\in \mathbf{I}. For all j∈j\in {2,...,n}\{2, . . . , n\}, prove that there exists a continuous mapping gj:R→Rg_j:\mathbf{R}\rightarrow \mathbf{R} such that fj(x)=gj(f1(x))f_j(x) =g_j(f_1(x)) for all x∈Ix\in \mathbf{I}. Deduce that f(I)f(\mathbf{I}) is isotopic to a segment. (b) Prove that there exists a real number δ>0\delta >0 and a continuous injective mapping j:[−δ,1+δ]×Bn−1→Rnj: [-\delta ,1 +\delta ]\times \mathbf{B}_{n-1}\rightarrow \mathbf{R}^n such that j(t,0)=f(t)j(t,0) =f(t) for all t∈It\in \mathbf{I}. Deduce from Exercise 30 that, for all τ∈[0,1[\tau \in [0,1[, the set f(I)f(\mathbf{I}) is isotopic to f([τ,1])f([\tau ,1]).

(c) Prove that f(I)f(\mathbf{I}) is isotopic to a segment.

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.