Bourbaki

Exercise 27, § 9

General Topology, I, p. 110

; now prove that the canonical mapping ψ:X′′→X~\psi : X'' \to \tilde{X} is surjective and that X~\tilde{X} is compact. Every continuous mapping ff of X into a compact space Y can therefore be written in one and only one way f=h∘ψ∘φf = h \circ \psi \circ \varphi, where h:X~→Yh : \tilde{X} \to Y is continuous.

27) If X is a discrete space, now prove that the spaces X′′X'' and X~\tilde{X} defined in Exercise 26 are identical, and that if T\mathfrak{T} is the topology of the space X′X' defined in Exercise 25, the space X′′X'' is identified with the space X′X' endowed with the semi-regular topology T∗\mathfrak{T}^* associated with T\mathfrak{T} (I, p. 103, Exercise 20). Moreover, the set X′′X'' is identified canonically with the set of ultrafilters on X, and one says that the compact space X′′X'' is the space of ultrafilters of X.

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.