Bourbaki

Exercise 30, § 9

General Topology, I, p. 111

Bourbaki marks this one as harder than the rest.

One says that a topological space X is locally quasi-compact if every point of X admits a fundamental system of quasi-compact neighbourhoods.

a) Now prove that in a locally quasi-compact space, every quasi-compact set admits a fundamental system of quasi-compact neighbourhoods.

b) Now prove that every locally closed subspace of a locally quasi-compact space is locally quasi-compact.

*c) On the Euclidean closed disk B: ∥x∥≤1\|x\| \leq 1 in the plane R2\mathbf{R}^2, consider the topology T\mathfrak{T} finer than the topology T0\mathfrak{T}_0 induced by that of R2\mathbf{R}^2, such that for T\mathfrak{T} the neighbourhood filter of a point x≠(1,0)x \neq (1, 0) of B is identical with the neighbourhood filter of this point for T0\mathfrak{T}_0, but a fundamental system of neighbourhoods of (1,0)(1, 0) is formed by the unions of {(1,0)}\{(1, 0)\} and the trace on the open disk B0:∥x∥<1B_0: \|x\| < 1 of an open disk with center (1,0)(1, 0). Let Y be the set B endowed with the topology T\mathfrak{T}; consider in Y the equivalence relation whose classes are the set S of the x≠(1,0)x \neq (1, 0) such that ∥x∥=1\|x\| = 1, and the subsets of Y reduced to a point not in S. Now prove that the quotient space X=Y/RX = Y/R is quasi-compact but not locally quasi-compact.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.