Bourbaki

Exercise 27, § 6

General Topology, III, p. 85

Let AA be a separated integral topological ring, A′A' the set of elements ≠0\neq 0 of AA, RR the equivalence relation xt=yzxt = yz between the pairs (x,y)(x, y) and (z,t)(z, t) in A×A′A \times A'; the quotient set K=(A×A′)/RK = (A \times A')/R is the field of fractions of AA.

a) Endow A′A' with the topology induced by that of AA, A×A′A \times A' with the product topology. Prove that if the relation RR is open, the quotient topology of that of A×A′A \times A' by RR is a separated topology on KK, compatible with the field structure of KK.

b) Suppose that, for every a≠0a \neq 0 in AA, the mapping x↦axx \mapsto ax of AA into itself is open. Prove that RR is then open.

c) Suppose that KK is endowed with a topology T\mathfrak{T} compatible with its ring structure and inducing on AA (canonically embedded in KK) the given topology. Deduce from a) and b) that there exists on KK a separated topology T′\mathfrak{T}', less fine than T\mathfrak{T} and compatible with the field structure of KK.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.