Bourbaki

Exercise 29, § 6

General Topology, III, p. 85

Bourbaki marks this one as harder than the rest.

a) Now prove that there exists a double sequence (Enm)(E_{nm}) of finite symmetric subsets of Z\mathbf{Z} defined for 0≤n≤m0 \leq n \leq m, containing 0, not reduced to 0 for m≥1m \geq 1, and satisfying the following conditions: 1° for every n≥0n \geq 0, the sets En+1,m+(⋃r=n+1mEn+1,r)E_{n+1,m} + (\bigcup_{r=n+1}^m E_{n+1,r}), En+1,m⋅(⋃r=n+1mEn+1,r)E_{n+1,m} \cdot (\bigcup_{r=n+1}^m E_{n+1,r}) and k⋅En+1,mk \cdot E_{n+1,m} for k≤n+1k \leq n+1 are all contained in the union ⋃s=nmEns\bigcup_{s=n}^m E_{ns}; 2° if ymy_m denotes the smallest element >0> 0 of E0,m−{0}E_{0,m} - \{0\}, and zmz_m the greatest element of E0,mE_{0,m}, one has ym+1≥zm+m+1y_{m+1} \geq z_m + m + 1; 3° En+1,m⊂En,mE_{n+1,m} \subset E_{n,m}. (Supposing the EpqE_{pq} determined for p≤q≤mp \leq q \leq m, determine successively Em+1,m+1,Em,m+1,…,E0,m+1E_{m+1,m+1}, E_{m,m+1}, \ldots, E_{0,m+1} by descending recurrence).

b) Let VnV_n denote the union of the EnmE_{nm} for all m≥nm \geq n. Now prove that (Vn)(V_n) is a fundamental system of neighbourhoods of 0 for a topology on Z\mathbf{Z} compatible with the ring structure of Z\mathbf{Z}, and for which no subgroup of Z\mathbf{Z} other than Z\mathbf{Z} is open.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.