Bourbaki

Exercise 23, § 1

General Topology, IX, p. 90

Bourbaki marks this one as harder than the rest.

Let X,YX, Y be two completely regular spaces. Now prove that the three conditions are equivalent: α)\alpha) X×YX \times Y is weierstrassian; β)\beta) the canonical mapping β(X×Y)→β(X)×β(Y)\beta(X \times Y) \to \beta(X) \times \beta(Y) is a homeomorphism; γ)\gamma) for every numerical function ff bounded and continuous in X×YX \times Y and every ε>0\varepsilon > 0, there exists a finite open covering of X×YX \times Y formed of sets of the form Ui×ViU_i \times V_i, where UiU_i is open in XX and ViV_i open in YY, such that the oscillation of ff in each of the Ui×ViU_i \times V_i is ≤ε\leq \varepsilon. (To see that α\alpha) implies β)\beta), use Exercise 22 c); to see that γ)\gamma) implies α)\alpha), use Exercise 22 d)).

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.