Bourbaki

Exercise 17, § 2

General Topology, X, p. 46

Bourbaki marks this one as harder than the rest.

Let XX be a compact space, Γ\Gamma a countable group of homeomorphisms of XX; suppose that the orbit space X/ΓX/\Gamma is separated (hence compact).

a) Now prove that the orbit Γ(x)\Gamma(x) of every x∈Xx \in X is a finite set (notice that if this set were infinite, it would have no isolated point and use the Baire theorem (IX, p. 55, th. 1)).

b) For each point x0∈Xx_0 \in X, let Δ(x0)\Delta(x_0) be the distinguished subgroup of Γ\Gamma formed by the homeomorphisms leaving invariant all the points of the orbit Γ(x0)\Gamma(x_0). Now prove that if Δ(x0)\Delta(x_0) has a finite number of generators, the group Γ\Gamma is equicontinuous at the point x0x_0. (Let fif_i (1≤i≤m1 \leq i \leq m) be the generators of Δ(x0)\Delta(x_0), gkg_k (1≤k≤n1 \leq k \leq n) representatives of each of the classes of the group Γ\Gamma modulo Δ(x0)\Delta(x_0) distinct from Δ(x0)\Delta(x_0); take a neighbourhood VV of x0x_0 such that none of the sets fi(V)f_i(V), fi−1(V)f_i^{-1}(V) meets one of the sets gk(V)g_k(V); then use the fact that the equivalence relation defined by Γ\Gamma is closed (I, p. 78, prop. 8)).

c) Without assumption on Δ(x0)\Delta(x_0), suppose that x0x_0 has a fundamental system of connected neighbourhoods in XX; show that Γ\Gamma is equicontinuous at the point x0x_0 (method analogous to that of b)). Deduce that if XX is locally connected, Γ\Gamma is equicontinuous.

d) Take for XX the compact subspace of R\mathbf{R} formed by 0, 1 and the points 1/n1/n and 1+1n1 + \frac{1}{n} (nn integer ≥2\geq 2); give an example of a countable group Γ\Gamma of homeomorphisms of XX such that X/ΓX/\Gamma is separated, and which is not equicontinuous.

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.