Bourbaki

Exercise 4, § 1

Tag 025R, permanent. Cite it as [Bourbaki, Tag 025R].

Spectral Theories, I, p. 153

Let AA be a commutative algebra over C\mathbf{C}, II an ideal of A,h,h the canonical injection of II into AA, and SS the set of χ∈X′(A)\chi \in \mathsf{X}'(A) which vanish on II. a) X′(h)\mathsf{X}'(h) is surjective.

b) X′(h)∣(X′(A)\mathsf{X}'(h)|(\mathsf{X}'(A) - S) is a homeomorphism of X′(A)\mathsf{X}'(A) - S onto X(I)\mathsf{X}(I). (Let χ0∈X′(A)\chi_0\in \mathsf{X}'(A) - S. Let x1,...,xn∈A,ε>0x_1, . . . , x_n\in A,\varepsilon >0, and let V be the neighbourhood of χ0\chi_0 in X′(A)\mathsf{X}'(A) defined by ∣(χ−χ0)(xi)∣⩽ε,(i=1,...,n)|(\chi -\chi_0)(x_i)|\leqslant \varepsilon ,(i= 1, . . . , n). Let u0∈Iu_0\in I such that χ0(u0)=1\chi_0(u_0) = 1. We have ui=u0xi∈Iu_i=u_0x_i\in I. Then if ∣(χ−χ0)(ui)∣⩽δ(i=0,1,...,n)|(\chi -\chi_0)(u_i)|\leqslant \delta (i= 0,1, . . . , n) with δ\delta sufficiently small, we have χ∈V\chi \in V.)

Solution

No solution has been written yet.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.