Bourbaki

Exercise 16, § 4

Tag 02BS, permanent. Cite it as [Bourbaki, Tag 02BS].

Spectral Theories, I, p. 176

Let A be a unital Banach algebra, x∈Ax\in A, and let kk be an integer ⩾0\geqslant 0. Let U\mathbf{U} be the set of complex numbers of modulus 1.

a) Suppose that SpA(x)⊂U_A(x)\subset \mathbf{U} and that ∥R(x,λ)∥=O((1−∣λ∣)k)\|R(x, \lambda )\|= O((1- |\lambda |)^k) when ∣λ∣|\lambda | tends to 1. Prove that ∥xn∥=O(∣n∣k)\|x^n\|= O(|n|^k) when nn tends to ±∞\pm \infty. (For every δ>1\delta >1, prove that

2π∥xn∥⩽Mδkn+Mδ−1k−n 2\pi \|x^n\|\leqslant M\delta^n_k+ M\delta^{-n}_{-1k}

(δ−1)(1−δ(\delta -1)(1-\delta )

where M is independent of nn and δ\delta. Take δ=n/(n−k)\delta =n/(n-k) when nn tends to +∞,δ=n/(n+k)+\infty ,\delta =n/(n+k) when nn tends to −∞.)-\infty .)

b) Suppose that ∥xn∥=O(∣n∣k)\|x^n\|= O(|n|^k) when nn tends to ±∞\pm \infty. Prove that SpA(x)⊂U_A(x)\subset \mathbf{U} and that ∥R(λ,x)∥=O((1−∣λ∣)k+1)\|R(\lambda , x)\|= O((1- |\lambda |)^{k+1}) when ∣λ∣|\lambda | tends to 1. (We have ϱ(x)=ϱ(x−1)=1\varrho (x) =\varrho (x^{-1}) = 1, hence SpA(x)⊂U_A(x)\subset \mathbf{U}. For ∣λ∣<1|\lambda |<1,

R(λ,x)=−x−1(1+λx−1+λ2x−2+λ3x−3+...) R(\lambda , x) =-x^{-1}(1 +\lambda x^{-1}+\lambda^2x^{-2}+\lambda^3x^{-3}+. . .)

Deduce an upper bound for ∥R(λ,x)∥\|R(\lambda , x)\|, and reason in an analogous manner if ∣λ∣>1|\lambda |>1.)

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.