Bourbaki

Exercise 3, § 3

Tag 031O, permanent. Cite it as [Bourbaki, Tag 031O].

Spectral Theories, IV, p. 331

Let n∈Nn\in \mathbf{N}. Let μn\mu_n denote Lebesgue measure on Rn\mathbf{R}^n.

a) Let H1\mathscr{H}_1 be the image of the mapping ∂1:D(Rn)→D(Rn)\partial_1:\mathscr{D}(\mathbf{R}^n)\rightarrow \mathscr{D}(\mathbf{R}^n); it is the space of φ∈D(Rn)\varphi \in \mathscr{D}(\mathbf{R}^n) such that

∫Rφ(x,y)dμ1(x)=0 \int_{\mathbf{R}}\varphi (x, y)d\mu_1(x) = 0

for every y∈Rn−1y\in \mathbf{R}^{n-1}.

b) Let φ0∈D(R)\varphi_0\in \mathscr{D}(\mathbf{R}) whose integral over R\mathbf{R} is equal to 1. For every φ∈D(Rn)\varphi \in \mathscr{D}(\mathbf{R}^n), there exists φ1∈H1\varphi_1\in \mathscr{H}_1 such that

φ(x,y)=φ1(x,y)+φ0(x)∫Rφ(t,y)dμ1(t) \varphi (x, y) =\varphi_1(x, y) +\varphi_0(x)\int_{\mathbf{R}}\varphi (t, y)d\mu_1(t)

for every (x,y)∈R×Rn−1(x, y)\in \mathbf{R}\times \mathbf{R}^{n-1}.

c) For every distribution f∈D′(Rn)f\in \mathscr{D}'(\mathbf{R}^n), there exists g∈D′(Rn)g\in \mathscr{D}'(\mathbf{R}^n) such that ∂1g=f\partial_1g=f. If g1g_1 and g2g_2 in D′(Rn)\mathscr{D}'(\mathbf{R}^n) satisfy ∂1g1=∂1g2=f\partial_1g_1=\partial_1g_2=f, then there exists a distribution h∈D′(Rn−1)h\in \mathscr{D}'(\mathbf{R}^{n-1}) such that

⟨g1−g2,φ⟩=⟨h,ψ⟩ \langle g_1-g_2, \varphi \rangle =\langle h, \psi \rangle

for every φ∈D(Rn)\varphi \in \mathscr{D}(\mathbf{R}^n), where ψ∈D(Rn−1)\psi \in \mathscr{D}(\mathbf{R}^{n-1}) is defined by

ψ(y)=∫Rφ(t,y)dμ1(t) \psi (y) =\int_{\mathbf{R}}\varphi (t, y)d\mu_1(t)

d) Let U be a connected open set of Rn\mathbf{R}^n. Let f∈D′(U)f\in \mathscr{D}'(U) be a distribution such that ∂if=0\partial_if= 0 for 1⩽i⩽n1\leqslant i\leqslant n. The distribution ff is the distribution associated with a constant function.

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Machine translation of the English, by gpt-5.4. Not checked by a person.