Bourbaki

Exercise 29, § 5

Tag 0384, permanent. Cite it as [Bourbaki, Tag 0384].

Spectral Theories, IV, p. 366

Let E be a complex Hilbert space. We denote by Tb\mathscr{T}_b (resp. Ts,Tf\mathscr{T}_s,\mathscr{T}_f) the Banach-space topology of L(E)\mathscr{L}(E) (resp. the topology of simple convergence, the locally convex topology defined by the seminorms u↦u\mapsto ⟨x∣u(y)⟩\langle x|u(y)\rangle for (x,y)∈E×E(x, y)\in E\times E).

a) Let λ0∈C−R\lambda_0\in \mathbf{C}-\mathbf{R}. The Tb\mathscr{T}_b-resolvent topology (resp. the Ts\mathscr{T}_s-resolvent topology) is the coarsest topology on A(E)\mathscr{A}(E) for which the mapping u↦R(u,λ0)u\mapsto R(u, \lambda_0) of A(E)\mathscr{A}(E) into L(E)\mathscr{L}(E) endowed with the topology Tb\mathscr{T}_b (resp. Ts\mathscr{T}_s) is continuous.

b) The Tf\mathscr{T}_f-resolvent topology coincides with the Ts\mathscr{T}_s-resolvent topology.

c) Let X⊂L(E)X\subset \mathscr{L}(E) be a bounded set of Hermitian endomorphisms of E. The topology induced on X by the Tb\mathscr{T}_b-resolvent topology (resp. the Ts\mathscr{T}_s-resolvent topology) coincides with the topology induced by the topology Tb\mathscr{T}_b ((esp. the topology Ts\mathscr{T}_s).

d) The property of question a) does not hold for the Tf\mathscr{T}_f-resolvent topology. e) Give an example of a sequence (un)(u_n) of partial self-adjoint operators which converges for the Tb\mathscr{T}_b-resolvent topology and of a function f∈Cb(R)f\in \mathscr{C}_b(\mathbf{R}) such that f(un)f(u_n) does not converge to f(u)f(u) in L(E)\mathscr{L}(E).

f) Let (un)(u_n) be a sequence of partial self-adjoint operators on E and let uu be a partial self-adjoint operator on E. If there exists a dense subspace F of EuE_u, contained in dom(unu_n) for every nn, such that un(x)u_n(x) converges to u(x)u(x) for every x∈Fx\in F, then (un)(u_n) converges to uu for the Ts\mathscr{T}_s-resolvent topology.

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Machine translation of the English, by gpt-5.4. Not checked by a person.