Bourbaki

Exercise 2, § 1

Commutative Algebra, I, 39

Consider a commutative diagram of commutative groups

A→uB→vCa↓b↓c↓A′→u′B′→v′C′a′↓b′↓A′′→u′′B′′ \begin{array}{ccccc} A & \xrightarrow{u} & B & \xrightarrow{v} & C \\ a \downarrow & & b \downarrow & & c \downarrow \\ A' & \xrightarrow{u'} & B' & \xrightarrow{v'} & C' \\ a' \downarrow & & b' \downarrow & & \\ A'' & \xrightarrow{u''} & B'' \end{array}

Suppose that: (1) (u,v)(u, v) and (b,b′)(b, b') are exact sequences; (2) v′∘u′=0v' \circ u' = 0 and a′∘a=0a' \circ a = 0; (3) cc and u′u' are injective and a′a' is surjective. Show that under these conditions u′′u'' is injective.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.