Bourbaki

Exercise 14, § 2

Commutative Algebra, I, 45

Bourbaki marks this one as harder than the rest.

Let A, B be two rings, E a left A-module, F an (A, B)-bimodule and G a right B-module; consider the canonical homomorphism (Algebra, Chapter II, § 4, Exercise 5)

is⁡:Hom⁡B(F,G)⊗AE→Hom⁡B(Hom⁡A(E,F),G) \operatorname{is}: \operatorname{Hom}_B(F, G) \otimes_A E \to \operatorname{Hom}_B(\operatorname{Hom}_A(E, F), G)

such that (σ(u⊗x))(v)=u(v(x))(\sigma(u \otimes x))(v) = u(v(x)) for all x∈E,u∈Hom⁡B(F,G),v∈Hom⁡A(E,F)x \in E, u \in \operatorname{Hom}_B(F, G), v \in \operatorname{Hom}_A(E, F).

Show that, if G is an injective B-module (Algebra, Chapter II, § 2, Exercise 11) and E finitely presented, is is bijective. (Consider first the case where E is free and finitely generated.)

Solution

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Transcribed from the printed volume. Not translated.