Bourbaki

Exercise 16, § 2

Commutative Algebra, II, 127

Let AA be a topological ring (not necessarily commutative). The topology on AA is called (left) linear if the open left ideals of AA form a fundamental system of neighbourhoods of 0. If this is so, the set F\mathscr{F} of open left ideals of AA satisfies the following conditions: (1) Every left ideal of AA containing an ideal m∈Fm \in \mathscr{F} belongs to F\mathscr{F}. (2) Every finite intersection of ideals of F\mathscr{F} belongs to G\mathscr{G}. (3) If m∈Fm \in \mathscr{F} and a∈Aa \in A, the left ideal nn consists of those x∈Ax \in A such that xa∈mxa \in m belongs to F\mathscr{F}.

Conversely, if a set F\mathscr{F} of left ideals of a ring AA satisfies these three conditions, there exists a unique topology compatible with the ring structure on AA and for which F\mathscr{F} is the set of open left ideals of AA. Such a set F\mathscr{F} of left ideals is called (left) topologizing.

Solution

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Transcribed from the printed volume. Not translated.