Bourbaki

Exercise 26, § 2

Commutative Algebra, II, 135

Bourbaki marks this one as harder than the rest.

(a) Show that every Zorn ring A (Algebra, Chapter VIII, § 6, Exercise 13) with no nil ideal ≠0\neq 0 is left neat; in particular, every absolutely flat ring and every primitive ring whose socle is not reduced to 0 is a left neat ring.

(b) Let A be a left primitive ring whose socle is not reduced to 0; show that, if A is represented as a dense subring of a ring of endomorphisms End⁡D(V)\operatorname{End}_D(V) of a vector space (Algebra, Chapter VIII, § 5, Exercise 10), the ring AFA_{\mathscr{F}} corresponding to A (Exercise 25) is isomorphic to End⁡D(V)\operatorname{End}_D(V).

(c) Show that every quasi-simple ring A (Algebra, Chapter VIII, § 5, Exercise 5) is left and right neat and that the corresponding ring AFA_{\mathscr{F}} is quasi-simple. Deduce that, for every ring B not reduced to 0, there exists a homomorphism ϕ:B→R\phi : B \to R to a ring R which is quasi-simple, absolutely flat and such that RsR_s is an injective R-module.

(d) Let A be a left Noetherian ring with no nilpotent ideals. Show that A is left neat and that the corresponding ring AFA_{\mathscr{F}} is a semi-simple ring ("Goldie's Theorem"; use Exercise 24 (a) and, on the other hand, use Algebra, Chapter VIII, § 2, Exercise 7, noting that in the absolutely flat ring AFA_{\mathscr{F}} there cannot exist any family of idempotents which are pairwise orthogonal, unless A contained an infinite direct sum of left ideals ≠0\neq 0). Show that, if s∈As \in A is not a right divisor of 0 in A, it is invertible in AFA_{\mathscr{F}} and conversely; the set S of these elements is a multiplicative subset of A. Show that F\mathscr{F} is the set of left ideals of A which meet S (to see that the ideals of A meeting S belong to F\mathscr{F}, note that the elements of S are not left divisors of 0 in A; to see that every f∈Ff \in \mathscr{F} contains an element of S, represent each simple component of AFA_{\mathscr{F}} as an endomorphism ring of an n-dimensional vector space E and define by induction n elements u1,…,unu_1, \ldots, u_n such that uiuj=0u_i u_j = 0 for j<ij < i and ui2≠0u_i^2 \neq 0, the uiu_i being of rank 1; finally show that the kernel of s=u1+…+uns = u_1 + \ldots + u_n is zero). Deduce that (AF,jA)(A_{\mathscr{F}}, j_A) is a ring of left fractions of A with denominators in S (Exercise 22).

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.