Bourbaki

Exercise 2, § 3

Commutative Algebra, II, 136

(a) Let AA be a (commutative) local ring whose maximal ideal mm is principal and such that ⋂n≥1mn=0\bigcap_{n \geq 1} m^n = 0 (cf. Chapter III, § 3, no. 2, Corollary to Proposition 4). Show that the only ideals ≠0\neq 0 and #A\#A of AA are the powers mnm^n; deduce that AA is Noetherian and is either a discrete valuation ring (Chapter VI) or a quasi-principal ring in which 1 is an indecomposable idempotent (Algebra, Chapter VII, § 1, Exercise 6).

(b) Let AA be the ring of germs at the point t=0t = 0 of real-valued functions defined and continuous in a neighbourhood of 0 and differentiable at the point 0 (General Topology, Chapter I, 3rd ed., § 6, no. 10). Show that AA is a local ring whose maximal ideal mm is generated by the germ of the function j:t↦t;mn≠0j : t \mapsto t ; m^n \neq 0 for all nn but AA is not a principal ideal domain. If cc is the germ of the function t↦exp⁡(−1/t2)t \mapsto \exp(-1/t^2) and pp a prime ideal of AA not containing cc, show that the quotient ring B=A/pB = A/p is a local integral domain which is not a principal ideal domain and in which the maximal ideal is principal.

Solution

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