Exercise 3, § 3
Commutative Algebra, II, 136
Bourbaki marks this one as harder than the rest.
Let be a local ring (not necessarily commutative, cf. Exercise 1) and its Jacobson radical.
(a) Let be a free left -module and an element of . Let be a basis of for which the number of components of is the least possible; if , let be the set of such that . Show that none of the () belongs to the right ideal of generated by the others.
(b) With the hypotheses and notation of (a), let P, Q be two complementary submodules of L such that ; for all , let , where , . Show that the family of for and for is a basis of L. (Prove, using (a), that, if , the components such that and necessarily belong to m and use Corollary 2 to Proposition 4.) Deduce that there exists a free submodule of P which contains x and is a direct factor of P.
(c) Show that every projective A-module P is free (using Kaplansky's Theorem (Algebra, Chapter 11, § 2, Exercise 4), reduce it to the case where P is generated by a countable family of elements and apply (b) to this case).
(d) Give an example of a local ring A and a flat A-module M which is not free and satisfies (take ). (In Chapter III, § 3, we shall give examples of faithfully flat A-modules which are not free over a Noetherian local ring A.)
(e) Let A be a local ring and M a finitely generated flat A-module. Show that M is a free A-module (use Exercise 23 (e) of Chapter I, § 2).
Solution
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