Bourbaki

Exercise 15, § 2

Commutative Algebra, III, 237

(a) Let EE be a linearly topologized A-module (Exercise 14). For a filter base B\mathfrak{B} on EE consisting of linear varieties to admit a cluster point, it is necessary and sufficient that there exists a convergent filter base B′⊃B\mathfrak{B}' \supset \mathfrak{B} consisting of linear affine varieties. EE is said to be linearly compact if it is Hausdorff and every filter base on EE consisting of affine linear varieties admits at least one cluster point. Every Artinian module is linearly compact with the discrete topology. Every linearly compact submodule of a Hausdorff linearly topologized module FF is closed in FF.

(b) If EE is a linearly compact A-module and uu a continuous linear mapping of EE to a Hausdorff linearly topologized A-module FF, u(F)u(F) is a linearly compact submodule of FF.

(c) Let EE be a Hausdorff linearly topologized A-module and FF a closed submodule of EE. For EE to be linearly compact, it is necessary and sufficient that FF and E/FE/F be so.

(d) Every product of linearly compact modules is linearly compact (consider a filter base which is maximal among the filter bases consisting of affine linear varieties.

(e) Let (Eα,fαβ)(E_\alpha, f_{\alpha\beta}) be an inverse system of linearly topologized modules relative to a directed indexing set; suppose that the fαβf_{\alpha\beta} are continuous linear mappings and that, for α≤β\alpha \leq \beta, fαβ−1(0)f_{\alpha\beta}^{-1}(0) is a linearly compact submodule of EαE_\alpha. Let E=lim⁡←EαE = \lim_{\leftarrow} E_\alpha, and let fαf_\alpha be the canonical mapping E→EαE \to E_\alpha; show that, for all α\alpha, fα(E)=⋂α≤βfαβ(Eβ)f_\alpha(E) = \bigcap_{\alpha \leq \beta} f_{\alpha\beta}(E_\beta) (in particular, if the fαβf_{\alpha\beta} are surjective, so are the fαf_\alpha) and fα−1(0)f_\alpha^{-1}(0) is linearly compact (use (d) and General Topology, Chapter I, Appendix, no. 2, Theorem 1).

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