Bourbaki

Exercise 18, § 2

Commutative Algebra, III, 238

Bourbaki marks this one as harder than the rest.

In an A-module E, a submodule M≠EM \neq E is called sheltered if there exists a least element in the set of submodules ≠0\neq 0 in E/ME/M.

(a) Show that every submodule N≠EN \neq E of E is an intersection of sheltered submodules (for all x∉Nx \notin N, consider a maximal element in the set of submodules of E containing N and not containing xx).

(b) Let T\mathscr{T} be a Hausdorff linear topology on E and let T∗\mathscr{T}^* be the linear topology with fundamental system of neighbourhoods of 0 the filter base generated by the submodules of E which are open under T\mathscr{T} and sheltered. Show that T∗\mathscr{T}^* is Hausdorff and that every submodule which is closed under T\mathscr{T} is also closed under T∗\mathscr{T}^* (note that every submodule which is closed under T\mathscr{T} is an intersection of submodules which are open under T\mathscr{T}). Deduce that, if E is complete with respect to T∗\mathscr{T}^*, it is complete with respect to T\mathscr{T} (General Topology, Chapter III, § 3, no. 5, Proposition 9).

(c) Suppose that T\mathscr{T} is linearly compact. Then show that T∗\mathscr{T}^* is linearly compact and is the coarsest Hausdorff linear topology coarser than T\mathscr{T}; in particular T∗\mathscr{T}^* is a minimal linear topology (Exercise 17). (Let B\mathfrak{B} be a filter base consisting of submodules closed under T\mathscr{T} whose intersection is 0; show that, for every submodule U which is open under T\mathscr{T} and sheltered, there exists M∈BM \in \mathfrak{B} such that M⊂UM \subset U, using Exercise 16 (d)).

(d) Let F be a Hausdorff linearly topologized A-module and T1\mathscr{T}_1 its topology; show that, if u:E→Fu : E \to F is a continuous linear mapping with respect to the topologies T\mathscr{T} and T1\mathscr{T}_1, uu is also continuous with respect to the topologies T∗\mathscr{T}^* and T1∗\mathscr{T}_1^*.

Solution

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Transcribed from the printed volume. Not translated.