Exercise 18, § 2
Commutative Algebra, III, 238
Bourbaki marks this one as harder than the rest.
In an A-module E, a submodule is called sheltered if there exists a least element in the set of submodules in .
(a) Show that every submodule of E is an intersection of sheltered submodules (for all , consider a maximal element in the set of submodules of E containing N and not containing ).
(b) Let be a Hausdorff linear topology on E and let be the linear topology with fundamental system of neighbourhoods of 0 the filter base generated by the submodules of E which are open under and sheltered. Show that is Hausdorff and that every submodule which is closed under is also closed under (note that every submodule which is closed under is an intersection of submodules which are open under ). Deduce that, if E is complete with respect to , it is complete with respect to (General Topology, Chapter III, § 3, no. 5, Proposition 9).
(c) Suppose that is linearly compact. Then show that is linearly compact and is the coarsest Hausdorff linear topology coarser than ; in particular is a minimal linear topology (Exercise 17). (Let be a filter base consisting of submodules closed under whose intersection is 0; show that, for every submodule U which is open under and sheltered, there exists such that , using Exercise 16 (d)).
(d) Let F be a Hausdorff linearly topologized A-module and its topology; show that, if is a continuous linear mapping with respect to the topologies and , is also continuous with respect to the topologies and .
Solution
No solution has been written yet.