Bourbaki

Exercise 19, § 2

Commutative Algebra, III, 239

Bourbaki marks this one as harder than the rest.

(a) Let E be a linearly compact A-module. Show that the following conditions are equivalent:

(α) For every continuous linear mapping uu from E to a Hausdorff linearly topologized A-module F, uu is a strict morphism (General Topology, Chapter III, § 2, no. 8) from E to F.

(β) For every closed submodule F of E, the quotient topology on E/F is a minimal topology (Exercise 17).

(γ) E is complete and there is a fundamental system (Uλ)(U_\lambda) of open neighbourhoods of 0 in E, consisting of submodules and such that the E/UλE/U_\lambda are Artinian modules.

(To see that (γ) implies (β), reduce it to the case where F=0F = 0 and use Exercises 17 and 18.)

If E satisfies the equivalent conditions (α), (β) and (γ), E is called strictly linearly compact.

(b) Let E be a Hausdorff linearly topologized A-module and F a closed submodule of E. For E to be strictly linearly compact, it is necessary and sufficient that F and E/F be so.

(c) Every inverse limit of strictly linearly compact modules is strictly linearly compact.

(d) Let E be a Hausdorff linearly topologized A-module and uu a linear mapping from E to a strictly linearly compact A-module F. Show that if the graph of uu is closed in E×FE \times F, uu is continuous (use Exercise 16 (c) and the fact that, if M is closed in E and E/ME/M is Artinian, M is open in E).

Solution

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Transcribed from the printed volume. Not translated.