Exercise 20, § 2
Commutative Algebra, III, 239
Bourbaki marks this one as harder than the rest.
(a) Show that a discrete linearly compact module cannot be the direct sum of an infinity of submodules which are not reduced to 0.
(b) Give an example of a minimal linear topology (Exercise 17) which is not linearly compact (consider an infinite direct sum of simple modules no two of which are isomorphic).
(c) Let E be a linearly compact module such that there exists a family of simple submodules whose sum is dense in E. Show that: (1) E is strictly linearly compact (apply (a) to the quotient of E by an open submodule); (2) E is isomorphic to the (topological) product of a family of discrete simple modules. (Consider the sets of maximal open submodules of E such that for every finite sequence of n distinct elements of , is the direct sum of n simple submodules. Show that there exists a maximal set (with respect to inclusion) and that the intersection of all the submodules G belonging to such a set is reduced to 0; use the fact that is an intersection of maximal open submodules and that for every maximal open submodules G of E there is at least one simple submodule of E not contained in G. Conclude by using the fact that E is strictly linearly compact.)
(d) Deduce from (c) that every linearly compact vector space over a field K is strictly linearly compact and isomorphic to a product .
Solution
No solution has been written yet.