Bourbaki

Exercise 27, § 2

Commutative Algebra, III, 243

Bourbaki marks this one as harder than the rest.

(a) Let A be a commutative ring with a linear topology. For every multiplicative subset S of A, let A{S−1}A\{S^{-1}\} denote the Hausdorff completion of the ring S−1AS^{-1}A with the topology for which a fundamental system of neighbourhoods of 0 consists of the ideals S−1UλS^{-1}U_\lambda, where (Uλ)(U_\lambda) is a fundamental system of neighbourhoods of 0 in A consisting of ideals of A. Show that A{S−1}A\{S^{-1}\} is canonically isomorphic to the inverse limit of the rings Sλ−1(A/Uλ)S_\lambda^{-1}(A/U_\lambda) where SλS_\lambda is the canonical image of S in A/UλA/U_\lambda. If A^\hat{A} is the Hausdorff completion of A, A{S−1}A\{S^{-1}\} is canonically isomorphic to A^{S′−1}\hat{A}\{S'-1\}, where S′S' is the canonical image of S in A^\hat{A}.

(b) For A{S−1}A\{S^{-1}\} to be reduced to 0, it is necessary and sufficient that, in A, 0 belong to the closure of S. Deduce an example where A is Hausdorff and complete but S−1AS^{-1}A is not so with the topology defined in (a).

(c) For every continuous homomorphism uu of A to a complete Hausdorff linearly topologized ring B such that u(S)u(S) consists of invertible elements of B, show that u=u′∘ju = u' \circ j, where j:A→A{S−1}j : A \to A\{S^{-1}\} is the canonical mapping and u′u' is continuous; moreover u′u' is determined uniquely.

(d) Let S1,S2S_1, S_2 be two multiplicative subsets of A and let S2′S'_2 be the canonical image of S2S_2 in A{S−1}A\{S^{-1}\}; define a canonical isomorphism of A{(S1S2)−1}A\{(S_1S_2)^{-1}\} onto A{S1−1}{S2′−1}A\{S_1^{-1}\}\{{S'_2}^{-1}\}.

(e) Let aa be an open ideal of A and let a{S−1}a\{S^{-1}\} be the Hausdorff completion of S−1aS^{-1}a with respect to the topology induced by that on S−1AS^{-1}A; show that a{S−1}a\{S^{-1}\} is canonically identified with an open ideal of A{S−1}A\{S^{-1}\} and that the discrete ring A{S−1}/a{S−1}A\{S^{-1}\}/a\{S^{-1}\} is isomorphic to S−1(A/a)S^{-1}(A/a). Conversely, if a′a' is an open ideal of A{S−1}A\{S^{-1}\}, its inverse image a in A is an open ideal such that a′=a{S−1}a' = a\{S^{-1}\}. In particular, the mapping p↦p{S−1}p \mapsto p\{S^{-1}\} is an increasing bijection of the set of open prime ideals of A not meeting S onto the set of open prime ideals of A{S−1}A\{S^{-1}\}.

(f) Let pp be an open prime ideal of A and let S=A−pS = A - p. Show that A{S−1}A\{S^{-1}\} is a local ring whose residue field is isomorphic to the field of fractions of A/pA/p.

(g) For every element f∈Af \in A, let A,,nA_{,,n} denote the ring A{Sf−1}A\{S_f^{-1}\}, where SfS_f is the multiplicative set of thef'' (n⩾0n \geqslant 0). If ff runs through a multiplicative subset S of A, the A,,nA_{,,n} form a direct system of rings whose direct limit is denoted by A{S}A_{\{S\}} (without any topology); define a canonical homomorphism

A{S}→A{S−1}. A_{\{S\}} \to A\{S^{-1}\}.

If S=A−pS = A - p, where pp is an open prime ideal of A, show that A{S}A_{\{S\}} is a local ring, the canonical homomorphism A{S}→A{S−1}A_{\{S\}} \to A\{S^{-1}\} is local and the residue fields of A,,nA_{,,n} and A{S−1}A\{S^{-1}\} are canonically isomorphic (cf. Chapter II, § 3, Exercise 16).

(h) Suppose that the topology on AA is the mm-adic topology for some ideal mm of AA, that AA is Hausdorff and complete and that m/m2m/m^2 is a finitely generated (A/m)(A/m)-module. Show that, if m′=m{S−1}m' = m\{S^{-1}\}, the topology on A′=A{S−1}A' = A\{S^{-1}\} is the m′m'-adic topology, m′=mA′m' = mA' and m′/m′2m'/{m'}^2 is a finitely generated (A′/m′)(A'/m')-module (use Proposition 14 of no. 10). If AA is Noetherian, so is A′A'.

Solution

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Transcribed from the printed volume. Not translated.