Bourbaki

Exercise 6, § 2

Commutative Algebra, III, 234

Bourbaki marks this one as harder than the rest.

Let AA be a commutative ring, EE and FF two AA-modules and (En)(E_n) (resp. (Fj)(F_j)) an exhaustive filtration on EE (resp. FF) consisting of sub-AA-modules. On the tensor product G=E⊗AFG = E \otimes_A F, consider the exhaustive filtration consisting of the Gn=∑i+j=nIm(Ei⊗AFj)G_n = \sum_{i+j=n} \mathrm{Im}(E_i \otimes_A F_j).

(a) Show that the composite canonical homomorphisms

(Ei/Ei+1)⊗A(Fj/Fj+1)→(Ei⊗AFj)/(Im(Ei⊗AFj+1)+Im(Ei+1⊗AFj))→Gi+j/Gi+j+1 (E_i/E_{i+1}) \otimes_A (F_j/F_{j+1}) \to \\ (E_i \otimes_A F_j)/(\mathrm{Im}(E_i \otimes_A F_{j+1}) + \mathrm{Im}(E_{i+1} \otimes_A F_j)) \to G_{i+j}/G_{i+j+1}
are the restrictions of a graded homomorphism of degree 0 (called canonical) gr(E)⊗Agr(F)→gr(E⊗AF)\mathrm{gr}(E) \otimes_A \mathrm{gr}(F) \to \mathrm{gr}(E \otimes_A F), which is surjective.

(b) Show that, if gr(E)\mathrm{gr}(E) is a flat AA-module, the AA-modules Em/EnE_m/E_n for m≤nm \leq n and E/EnE/E_n for n∈Zn \in \mathbf{Z} are flat.

(c) Suppose in the following that gr(E)\mathrm{gr}(E) is a flat AA-module and that EE is a flat AA-module (the second hypothesis being a consequence of the first if (En)(E_n) is a discrete filtration). Then the Hij=Ei⊗AFjH_{ij} = E_i \otimes_A F_j are canonically identified with submodules of G=E⊗AFG = E \otimes_A F (Chapter I, § 2, no. 5, Proposition 4). Show that, for any two finite subsets R,SR, S of Z×Z\mathbf{Z} \times \mathbf{Z},

(∗)(∑(i,j)∈RHij)∩(∑(h,k)∈SHhk)=Hsup⁡(i,h),sup⁡(j,k) (*) \quad \left( \sum_{(i,j) \in R} H_{ij} \right) \cap \left( \sum_{(h,k) \in S} H_{hk} \right) = H_{\sup(i,h), \sup(j,k)}
where in the second sum (i,j,h,k)(i,j, h, k) run through R×SR \times S. (If RR and SS are each reduced to a single element, use Chapter I, § 2, no. 6, Proposition 7. If pp is the greatest of the indices ii and hh appearing in the elements of RR or SS, qq the least of the indices jj and kk appearing in the elements of RR or SS, consider the images of the two sides of (*) under the canonical homomorphism

E⊗AFq→(E/Ep)⊗AFq E \otimes_A F_q \to (E/E_p) \otimes_A F_q

and argue by induction on Card(R) + Card(S).)

(d) Deduce from (c) that the canonical homomorphism defined in (a) is then bijective.

Solution

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Transcribed from the printed volume. Not translated.