Bourbaki

Exercise 10, § 2

Commutative Algebra, IV, 292

Let AA be a Noetherian ring and MM an AA-module. Show that the following properties are equivalent:

(α) Every finitely generated submodule of MM is of finite length. (β) MM is a direct limit of AA-modules of finite length. (γ) Every element p∈Ass⁡(M)p \in \operatorname{Ass}(M) is a maximal ideal of AA. (δ) Every element p∈Supp⁡(M)p \in \operatorname{Supp}(M) is a maximal ideal of AA.

Solution

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Transcribed from the printed volume. Not translated.