Bourbaki

Exercise 27, § 2

Commutative Algebra, IV, 298

Bourbaki marks this one as harder than the rest.

Let M be an A-module and Q a p-primary submodule of M. Q is said to be of exponent m if m is the smallest integer k such that pkM⊂Qp^k M \subset Q (cf. Exercise 3); if there exists no integer k with this property, Q is said to be of infinite exponent. If Q is of finite exponent, Q is also said to be strongly primary.

(a) Show that, if Q:p=QQ : p = Q, Q is of infinite exponent and that there exists α∈p\alpha \in p such that Q:(α)Q : (\alpha) is distinct from Q and is a p-primary submodule of M of infinite exponent.

(b) Give an example of a ring A and a p-primary ideal q of infinite exponent and such that q:p=qq : p = q (cf. § 1, Exercise 2).

(c) Let K be a field, A the polynomial ring K[Xn]n∈NK[X_n]_{n \in \mathbf{N}}, p the prime ideal of A generated by the XnX_n and q the p-primary ideal generated by the products XiXjX_i X_j (i≠ji \neq j) and the elements Xnn+1X_n^{n+1}. Show that for all a∈p−qa \in p - q, q:(a)q : (a) is of finite exponent, that q:p≠qq : p \neq q and that q:pq : p is a p-primary ideal of infinite exponent.

(d) Let Q be a p-primary submodule of M of finite exponent e. Show that the pkMp^k M for k<ek < e are all distinct and that the submodules Q:pkQ : p^k for k<ek < e are all distinct. For every ideal a of A show that either Q:a=QQ : a = Q or Q:aQ : a is a p-primary submodule in M distinct from M and of exponent ≤e−1\leq e - 1 (observe that if a⊂pa \subset p then pe−1M⊂Q:ap^{e-1} M \subset Q : a).

Solution

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Transcribed from the printed volume. Not translated.