Bourbaki

Exercise 28, § 2

Commutative Algebra, IV, 298

Bourbaki marks this one as harder than the rest.

A finitely generated A-module E is called strongly Laskerian if every submodule of E admits a primary decomposition in E all of whose elements are strongly primary (Exercise 27).

(a) Show that for a finitely generated A-module E to be strongly Laskerian, it is necessary and sufficient that it satisfy axiom (LA_{II}) of Exercise 23 and the axiom:

(LA_{III}) For every sequence (b_k) of ideals of A and every submodule F of E, the increasing sequence of submodules F: (b1b2…bk)(b_1 b_2 \ldots b_k) is stationary.

(To show that the conditions are necessary, use Exercise 27 (d). To see that they are sufficient, prove first that (LAIII_{III}) implies (LAI_I) and then that it implies that every primary ideal is of finite exponent, using Exercise 27 (a).)

(b) Show that the ring A defined in Exercise 23 (c) satisfies (LA_{III}).

(c) Let K be a field, V an infinite dimensional vector K-space and A=K⊕VA = K \oplus V the ring whose multiplication is defined by

(a,x)(a′,x′)=(aa′,ax′+a′x). (a, x)(a', x') = (aa', ax' + a'x).

Show that in A every ideal #A\#A is strongly primary, although A is not Noetherian.

(d) Let E be a finitely generated A-module and E′⊂EE' \subset E a finitely generated submodule. For E to be strongly Laskerian, it is necessary and sufficient that E' and E/E′E/E' be so. In particular, if A is a strongly Laskerian ring, every finitely generated A-module is strongly Laskerian. If E is a strongly Laskerian A-module, S^{-1}E is a strongly Laskerian S^{-1}A-module for every multiplicative subset S of A.

(e) Generalize Exercises 3 and 4 to strongly Laskerian modules.

Solution

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Transcribed from the printed volume. Not translated.