Bourbaki

Exercise 32, § 2

Commutative Algebra, IV, 300

A ring A is called primary if it is a local ring and its maximal ideal m is a nil ideal (*). Every ideal of A contained in m is then m-primary in A.

(a) Let A be a strongly Laskerian primary ring, so that in particular the maximal ideal m is nilpotent. Show that, if a, b are two ideals contained in m, necessarily a:b≠aa : b \neq a (use Exercise 30 (b)).

(b) A primary Noetherian ring is Artinian. Deduce that, for every finitely generated module M over a Noetherian ring A and every p-primary submodule N of M, there exists an integer m such that every strictly decreasing sequence (Mi/N)0≤i≤k(M_i/N)_0 \leq i \leq k of submodules of M/N for which the M_i are p-primary has length k≤mk \leq m (consider the A,-module MpM_p and note that Mp/NpM_p/N_p is annihilated by a power of pAppA_p).

(c) Show that an Artinian ring A in which every prime ideal ≠{0}\neq \{0\} is maximal is the direct composition of a finite number of primary rings.

Solution

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Transcribed from the printed volume. Not translated.