Bourbaki

Exercise 33, § 2

Commutative Algebra, IV, 300

Let A be a commutative ring. An ideal a of A is called primal if, in A/aA/a, the set of divisors of 0 is an ideal p/ap/a; the ideal p is then prime.

(*) For (commutative) Artinian rings this definition coincides with that of Algebra, Chapter VIII, §6, Exercise 20.

(a) Show that every primary ideal and every irreducible ideal is primal. (b) Let aa be an ideal of AA such that the set of ideals bb for which a:b≠aa : b \neq a has a greatest element pp; show that pp is prime and that aa is primal. \* Give an example of a primal ideal aa for which the above condition is not satisfied (cf. § 1, Exercise 2). \* (c) In a Noetherian ring AA characterize the primal ideals and give an example of a non-primary primal ideal (cf. § 1, Exercise 11 (b)).

Solution

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Transcribed from the printed volume. Not translated.