Bourbaki

Exercise 10, § 1

Commutative Algebra, V, 356

Let A be a completely integrally closed domain. Show that for every set I the polynomial domain A[Xi]i∈IA[X_i]_{i \in I} and the domain of formal power series A[[Xi]]i∈IA[[X_i]]_{i \in I} (Algebra, Chapter IV, § 5, Exercise 1) are completely integrally closed. (Use Proposition 4 of no. 4 and the following lemma: for every finite subset J of I and all P∈A[[Xi]]i∈JP \in A[[X_i]]_{i \in J}, let PJP_J be the formal power series in A[[Xi]]i∈JA[[X_i]]_{i \in J} derived from P by replacing by 0 in P all the X, of index i∉Ji \notin J; if P, Q are two formal power series such that PJP_J is divisible by QJQ_J in A[[Xi]]i∈JA[[X_i]]_{i \in J} for all J, then P is divisible by Q in A[[Xi]]i∈IA[[X_i]]_{i \in I}. For this note that, if J, J' are two finite subsets of I such that J⊂J′J \subset J' and PJ′=L′QJ′P_{J'} = L' Q_{J'}, and P=LQJP_{} = L Q_J, then L is obtained from L' by replacing by 0 in L' the X, of index i∈J′−Ji \in J' - J.)

Solution

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Transcribed from the printed volume. Not translated.