Exercise 12, § 1
Commutative Algebra, V, 356
It is set in small type as supplementary.
Let A be the ring of integral functions (with complex values) of a complex variable. It is an integral domain whose field of fractions is the field of meromorphic functions of a complex variable.
(a) Show that A is completely integrally closed. (b) For all , let be the set of zeros of (which is a closed subset of , which is discrete (and therefore countable) if ). If is an ideal of A distinct from A and (0), show that the for form a filter base . (If and are two integral functions with no zero in common, show, using the Mittag-Leffler Theorem, that it is possible to write , where and are in A, and deduce that ). Conversely, for every filter on to which a closed discrete subset of belongs, the set of for which is an ideal of A. Show that for every filter to which a closed discrete subset of belongs and for every ideal of A distinct from A and (0). (c) If is a prime ideal of A, show that is an ultrafilter. (Restricting it to the case where all the sets of are infinite, show that, if is the union of two infinite sets with no point in common, one of these sets belongs to .) Conversely, for every ultrafilter on to which a closed discrete subset of belongs, is a maximal ideal of A; obtain the converse. (d) Let be an ultrafilter on , the image under the canonical injection of a non-trivial ultrafilter on . Show that there exist non-maximal prime ideals of A such that . (For all and all , let be the order of at the point ( if ); consider the set of such that .) (e) With the notation of (d), let m be the maximal ideal . Show that the domain is not completely integrally closed (consider the meromorphic function ). \*
Solution
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