Bourbaki marks this one as harder than the rest.
Let K be a field, v a valuation on K, L an extension of K and v′ a valuation on L extending v; L is called an immediate extension (with respect to u′) if e(v′/v)=f(v′/v)=1. The completion K^ of K is an immediate extension of K.
(a) For L to be an immediate extension of K, it is necessary and sufficient that, for all x∈L−K, there exist y∈K such that v′(x−y)>v′(x).
(b) For every field K, show that there exists a maximal immediate extension L of K, that is, not admitting an immediate extension distinct from itself (use § 3, Exercise 3 (b)).
(c) Show that, if K is linearly compact with the topology defined by v, it admits no immediate extension other than itself (use (a), noting that, in the notation of (a), the set of v′(x−y) for y∈K has no greatest element in the value group of v′).
(d) Suppose that K is not linearly compact; let B be a well-ordered subset of the order group of v and (aβ)β∈B a family of elements of K such that, for λ<μ<v,
v(aλ−aμ)<v(aμ−av), but that there exists no
x∈K such that
v(x−aλ)=v(aλ−aγ) for every ordered pair
(λ,μ) such that
λ<μ. For every extension
E of
K and every extension
w of
v to
E, let
DE(λ) denote the set of
z∈E such that
v(z−aλ)≥γλ, where
γλ is the common value of the
v(aλ−aγ) for
λ<μ; the hypothesis is therefore that
⋂β∈BDK(β)=∅ (§ 5, Exercise 5 (a)). Let
Ω be an algebraic closure of
K and let
v0 be an extension of
v to
Ω; show that, if
P is a polynomial in
K[X], for there to exist
A∈B such that
v(P(aμ))=v(P(aλ)) for all
λ≤μ, it is necessary and sufficient that no zero of
P in
Ω belong to
⋂β∈BDΩ(β). If
P has this property and
E and
w have the same meaning as above, show that, for all
z∈⋂β∈BDE(β),
w(P(z)−P(aμ))>w(P(z))=v(P(aμ)) so long as
μ is large enough (decompose
P(X) into factors in
Ω[X]). Deduce that one of the following situations holds:
(1) Either ⋂β∈BDΩ(β)=∅ and, if θ is an element of this intersection whose degree over K is the least possible, K(θ) is an immediate extension of K distinct from K.
such that ⋂μDα(β)=∅; then there is a valuation v′ on K(X) extending v immediate extension of K (use the criterion in (a)).
(e) Deduce from (c) and (d) that for K to be linearly compact, it is necessary and sufficient that K have no immediate extension other than itself.