Bourbaki

Exercise 2, § 10

Commutative Algebra, VI, 472

Bourbaki marks this one as harder than the rest.

Let KK be a field, vv a valuation on KK, LL an extension of KK and v′v' a valuation on LL extending vv; LL is called an immediate extension (with respect to u′u') if e(v′/v)=f(v′/v)=1e(v'/v) = f(v'/v) = 1. The completion K^\hat{K} of KK is an immediate extension of KK.

(a) For LL to be an immediate extension of KK, it is necessary and sufficient that, for all x∈L−Kx \in L - K, there exist y∈Ky \in K such that v′(x−y)>v′(x)v'(x - y) > v'(x).

(b) For every field KK, show that there exists a maximal immediate extension LL of KK, that is, not admitting an immediate extension distinct from itself (use § 3, Exercise 3 (b)).

(c) Show that, if KK is linearly compact with the topology defined by vv, it admits no immediate extension other than itself (use (a), noting that, in the notation of (a), the set of v′(x−y)v'(x - y) for y∈Ky \in K has no greatest element in the value group of v′v').

(d) Suppose that KK is not linearly compact; let BB be a well-ordered subset of the order group of vv and (aβ)β∈B(a_\beta)_{\beta \in B} a family of elements of KK such that, for λ<μ<v\lambda < \mu < v,

v(aλ−aμ)<v(aμ−av), v(a_\lambda - a_\mu) < v(a_\mu - a_v),
but that there exists no x∈Kx \in K such that v(x−aλ)=v(aλ−aγ)v(x - a_\lambda) = v(a_\lambda - a_\gamma) for every ordered pair (λ,μ)(\lambda, \mu) such that λ<μ\lambda < \mu. For every extension EE of KK and every extension ww of vv to EE, let DE(λ)D_E(\lambda) denote the set of z∈Ez \in E such that v(z−aλ)≥γλv(z - a_\lambda) \geq \gamma_\lambda, where γλ\gamma_\lambda is the common value of the v(aλ−aγ)v(a_\lambda - a_\gamma) for λ<μ\lambda < \mu; the hypothesis is therefore that ⋂β∈BDK(β)=∅\bigcap_{\beta \in B} D_K(\beta) = \varnothing (§ 5, Exercise 5 (a)). Let Ω\Omega be an algebraic closure of KK and let v0v_0 be an extension of vv to Ω\Omega; show that, if PP is a polynomial in K[X]K[X], for there to exist A∈BA \in B such that v(P(aμ))=v(P(aλ))v(P(a_\mu)) = v(P(a_\lambda)) for all λ≤μ\lambda \leq \mu, it is necessary and sufficient that no zero of PP in Ω\Omega belong to ⋂β∈BDΩ(β)\bigcap_{\beta \in B} D_\Omega(\beta). If PP has this property and EE and ww have the same meaning as above, show that, for all z∈⋂β∈BDE(β)z \in \bigcap_{\beta \in B} D_E(\beta), w(P(z)−P(aμ))>w(P(z))=v(P(aμ))w(P(z) - P(a_\mu)) > w(P(z)) = v(P(a_\mu)) so long as μ\mu is large enough (decompose P(X)P(X) into factors in Ω[X]\Omega[X]). Deduce that one of the following situations holds:

(1) Either ⋂β∈BDΩ(β)≠∅\bigcap_{\beta \in B} D_\Omega(\beta) \neq \varnothing and, if θ\theta is an element of this intersection whose degree over KK is the least possible, K(θ)K(\theta) is an immediate extension of KK distinct from KK.

such that ⋂μDα(β)=∅\bigcap_{\mu} D_\alpha(\beta) = \varnothing; then there is a valuation v′v' on K(X)K(X) extending vv immediate extension of KK (use the criterion in (a)).

(e) Deduce from (c) and (d) that for KK to be linearly compact, it is necessary and sufficient that KK have no immediate extension other than itself.

Solution

No solution has been written yet.

Transcribed from the printed volume. Not translated.