Bourbaki

Exercise 21, § 8

Commutative Algebra, VI, 469

Let K be a field, vv a discrete valuation on K, A the ring of vv, π\pi a uniformizer of vv and k the residue field of vv.

(a) Let P, R be two polynomials in A[X]A[X], P being monic, and suppose that: (1) deg⁡(R)<h⋅deg⁡(P)\deg(R) < h \cdot \deg(P), where h≥1h \geq 1 is an integer; (2) the canonical image P‾\overline{P} of P in k[X]k[X] is irreducible. Show then that, if the polynomial Q=Ph+πRQ = P^h + \pi R is reducible in K[X]\mathbf{K}[X], necessarily h>1h > 1 and P‾\overline{P} divides the canonical image R‾\overline{R} of R in k[X]k[X]. Deduce that, for a given monic irreducible polynomial r(X)∈k[X]r(X) \in k[X] and a given integer h≥1h \geq 1, there exists a separable irreducible polynomial Q∈A[X]Q \in A[X] such that its canonical image Q‾\overline{Q} is equal to rhr^h.

(b) Let k′=k(α)k' = k(\alpha) be an algebraic extension of k of degree m and hh an integer ≥1\geq 1. Show that there exists an algebraic extension L of K of degree hmhm such that there is only a single valuation v′v' (up to equivalence) on L extending vv, that e(v′/v)=h,f(v′/v)=me(v'/v) = h, f(v'/v) = m and that the residue field of v′v' is isomorphic to k′k' (use (a)).

Solution

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