Bourbaki

Exercise 5, § 2

Commutative Algebra, VII, 556

(a) Let kk be a field, KK the field k(X,Y)k(X, Y) of rational functions in two indeterminates over kk and AA the polynomial ring K[Z]K[Z] in one indeterminate, which is a principal ideal domain. Let LL be the subfield k(Z,X+YZ)k(Z, X + YZ) of k(X,Y,Z)k(X, Y, Z); show that A∩LA \cap L is not a Dedekind domain (prove that there are prime ideals which are not maximal and ≠0\neq 0 in this ring).

(b) Let AA be a Dedekind domain which is not a principal ideal domain and for which the ideal class group C(A)C(A) is finite \* (the ring of integers of a finite algebraic extension of Q\mathbf{Q} has the latter property). \* Let (ai)i=1s(a_i)_{i=1}^s be a representative system of the group I(A)I(A) of fractional ideals ≠0\neq 0 modulo the subgroup of fractional principal ideals, consisting of integral ideals of AA and let pip_i (1≤i≤s1 \leq i \leq s) be the prime ideals dividing at least one of the aia_i. Let SS (resp. TT) denote the multiplicative set of elements x∈Ax \in \mathbf{A} such that vpi(x)=0v_{p_i}(x) = 0 for all ii (resp. consisting of 1 and the x∈Ax \in \mathbf{A} such that vq(x)=0v_q(x) = 0 for all the prime ideals qq distinct from the pip_i and vpi(x)≥1v_{p_i}(x) \geq 1 for all ii; the hypothesis implies that TT is not reduced to 1). Show that S−1AS^{-1}\mathbf{A} and T−1AT^{-1}\mathbf{A} are principal ideal domains and that A=(S−1A)∩(T−1A)\mathbf{A} = (S^{-1}\mathbf{A}) \cap (T^{-1}\mathbf{A}).

Solution

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Transcribed from the printed volume. Not translated.