Exercise 17, § 4
Commutative Algebra, VII, 576
Let k be a field, A the polynomial ring , L the free A-module and the canonical basis of L. Let M be the submodule of L generated by the two vectors . Show that there exists no pseudo-isomorphism from L to itself, whose restriction to M is a pseudo-isomorphism from M to the submodule N of the form where is a basis of the A-module L and a, b two ideals of A, or whose restriction to N is a pseudo-isomorphism from N to M. (By considering the determinantal ideals (Exercise 10) and noting that M is reflexive, attention may be confined to the case where N would also be reflexive and then necessarily , where
is an extremal element of A; show finally that, for every basis of L, can neither contain Au nor be contained in .)
Solution
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