Bourbaki

Exercise 17, § 4

Commutative Algebra, VII, 576

Let k be a field, A the polynomial ring k[X,Y]k[X, Y], L the free A-module A2A^2 and (e1,e2)(e_1, e_2) the canonical basis of L. Let M be the submodule of L generated by the two vectors (X+1)e1+Ye2,Ye1+Xe2(X + 1)e_1 + Ye_2, Ye_1 + Xe_2. Show that there exists no pseudo-isomorphism from L to itself, whose restriction to M is a pseudo-isomorphism from M to the submodule N of the form au+bvau + bv where (u,v)(u, v) is a basis of the A-module L and a, b two ideals of A, or whose restriction to N is a pseudo-isomorphism from N to M. (By considering the determinantal ideals (Exercise 10) and noting that M is reflexive, attention may be confined to the case where N would also be reflexive and then necessarily a=A,b=APa = A, b = AP, where

P(X,Y)=X(X+1)−Y2 P(X, Y) = X(X + 1) - Y^2

is an extremal element of A; show finally that, for every basis (u,v)(u, v) of L, M∩AuM \cap Au can neither contain Au nor be contained in APuAPu.)

Solution

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Transcribed from the printed volume. Not translated.