Bourbaki

Exercise 24, § 4

Commutative Algebra, VII, 578

Let AA be an integrally closed Noetherian domain. For a lattice MM (with respect to AA) to be reflexive, it is necessary and sufficient that it satisfy the following condition: for every ordered pair (a,b)(a, b) of elements of AA such that a≠0a \neq 0 and the homothety of ratio bb on A/aAA/aA is injective, the homothety of ratio bb on M/aMM/aM is then injective. (To see that the condition is necessary, consider two elements x,yx, y of MM such that ax+by=0ax + by = 0 and show that, for all p∈P(A)p \in P(A), y∈aMpy \in aM_p. To show that the condition is sufficient, use criterion (c) of Theorem 2 and observe (using Proposition 8 of § 1, no. 4) that the hypothesis may be written as

Ass⁡(M/aM)=Ass⁡(A/aA) \operatorname{Ass}(M/aM) = \operatorname{Ass}(A/aA)
for all a≠0a \neq 0 in AA and that for every module EE such that M⊂E⊂VM \subset E \subset V there exists a≠0a \neq 0 in AA such that aM⊂aE⊂M.aM \subset aE \subset M.)

Solution

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Transcribed from the printed volume. Not translated.