Bourbaki

Exercise 25, § 4

Algebra, I, 138

Bourbaki marks this one as harder than the rest.

Let E be a set and ff a mapping of EmE^m into E; we write

f(x1,x2,…,xm)=x1x2…xm; f(x_1, x_2, \ldots, x_m) = x_1 x_2 \ldots x_m;

suppose that ff satisfies the following conditions:

(1)

(x1x2…xm)xm+1…x2m−1=x1(x2x3…xm+1)xm+2…x2m−1(x_1 x_2 \ldots x_m) x_{m+1} \ldots x_{2m-1} = x_1 (x_2 x_3 \ldots x_{m+1}) x_{m+2} \ldots x_{2m-1}
identically; (2) For all a1,a2,…,am−1a_1, a_2, \ldots, a_{m-1}, the mappings

x↦xa1a2…am−1 x \mapsto x a_1 a_2 \ldots a_{m-1}
x↦a1a2…am−1x x \mapsto a_1 a_2 \ldots a_{m-1} x

are bijections of E onto E.

(a) Show that identically

(x1x2…xm)xm+1…x2m−1=x1x2…xi(xi+1…xi+m)xi+m+1…x2m−1(x_1 x_2 \ldots x_m) x_{m+1} \ldots x_{2m-1} = x_1 x_2 \ldots x_i (x_{i+1} \ldots x_{i+m}) x_{i+m+1} \ldots x_{2m-1}

for every index ii such that 1≤i≤m−11 \leq i \leq m-1 (argue by induction on ii, by considering the element

((x1x2…xm)xm+1…x2m−1)a1a2…am−1).((x_1 x_2 \ldots x_m) x_{m+1} \ldots x_{2m-1}) a_1 a_2 \ldots a_{m-1}).

(b) For all a1,a2,…,am−2a_1, a_2, \ldots, a_{m-2}, there exists u∈Eu \in E such that for all xx

x=xa1a2…am−2u=ua1a2…am−2x.x = x a_1 a_2 \ldots a_{m-2} u = u a_1 a_2 \ldots a_{m-2} x.

(c) In the set EkE^k of sequences (u1,u2,…,uk)(u_1, u_2, \ldots, u_k) of kk elements of EE (1≤k≤m−11 \leq k \leq m - 1) consider the equivalence relation RkR_k which states: for all x1,x2,…,xm−k,u1u2…ukx1x2…xm−k=v1v2…vkx1x2…xm−kx_1, x_2, \ldots, x_{m-k}, u_1u_2\ldots u_kx_1x_2\ldots x_{m-k} = v_1v_2\ldots v_kx_1x_2\ldots x_{m-k}; let EkE_k denote the quotient set Ek/RkE^k / R_k and GG the sum set (Set Theory, II, § 4, no. 8) of E1=E,E2,…,Em−1E_1 = E, E_2, \ldots, E_{m-1}. Let α∈Ei,β∈Ej\alpha \in E_i, \beta \in E_j; if (u1,u2,…,ui)(u_1, u_2, \ldots, u_i) is a sequence of class α\alpha, (v1,…,vj)(v_1, \ldots, v_j) a sequence of class β\beta, consider the sequence

(u1,u2,…,ui,v1,…,vj) (u_1, u_2, \ldots, u_i, v_1, \ldots, v_j)
in Ei+jE^{i+j} if i+j<mi + j < m, the sequence
(u1,u2,…,ui+j−m,(ui+j−m+1…uiv1v2…vj)) (u_1, u_2, \ldots, u_{i+j-m}, (u_{i+j-m+1}\ldots u_i v_1 v_2 \ldots v_j))
in Ei+j−m+1E^{i+j-m+1} if i+j≥mi + j \geq m; show that the class of this sequence in Ei+jE_{i+j} (resp. Ei+j−m+1E_{i+j-m+1}) depends only on the classes α\alpha and β\beta; it is denoted by α.β\alpha . \beta. Show that a group law is thus defined on GG, that H=Em−1H = E_{m-1} is a normal subgroup of GG and that the quotient group G/HG/H is cyclic of order m−1m - 1; prove finally that EE is identical with a class (mod. HH) which generates G/HG/H and that x1x2…xmx_1 x_2 \ldots x_m is just the composition, in the group GG, of the sequence (x1,x2,…,xm)(x_1, x_2, \ldots, x_m).

Solution

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Transcribed from the printed volume. Not translated.