Exercise 24, § 5
Algebra, I, 145
(a) Show that there exists a subgroup of which is isomorphic to and leaves fixed no element of (let operate by inner automorphisms on the set of its subgroups of order 5, which has 6 elements).
(b) Show that there exists an automorphism of which maps to . (Let operate on , where is chosen as above.)
(c) Show that the group of inner automorphisms of is of index 2 in the group of all automorphism of . (Let be an automorphism of ; show that maps a transposition either to a transposition or to a conjugate of . Using Exercise 23, show that in the first (resp. second) case (resp. ) is an inner automorphism.)
Solution
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