Bourbaki

Exercise 3, § 5

Algebra, I, 140

Let Γ\Gamma be the group of automorphisms of a group G and Δ\Delta the group of inner automorphisms of G; show that Δ\Delta is a normal subgroup of Γ\Gamma. For an automorphism σ\sigma of G to be permutable with all the inner automorphisms of G, it is necessary and sufficient that, for all x∈Gx \in G, x−1σ(x)x^{-1}\sigma(x) belong to the centre of G; deduce that, if the centre of G is reduced to the identity element, so is the centralizer of Δ\Delta in Γ\Gamma.

Solution

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Transcribed from the printed volume. Not translated.