Exercise 20, § 7
Algebra, I, 164
Bourbaki marks this one as harder than the rest.
We preserve the notation of the preceding exercise. Let H be a subgroup of G.
(a) Let be the set of S-connected subsets T of G such that if . Show that is inductive for the relation of inclusion.
(b) Let Y be a maximal element of . Show that , in other words Y is a system of representatives of the right cosets modulo H. (If is distinct from G, show that there exist and which are S-neighbours and deduce that belongs to .)
(c) Let be the set of elements such that Y and are neighbours. It is a symmetric subset of H. Show that an element belongs to if and only if and there exist with . Show that generates H. (If is the subgroup of H generated by , prove that is a connected S-component of G.) Obtain this result by means of Exercise 14 of § 4.
(d) Let be a subset of such that is the disjoint union of and (show that such a subset exists).
Show that is a basic family for H and in particular that H is a free group ("Nielsen-Schreier Theorem"). (Apply the criterion of Exercise 18(c) to H together with , noting that two elements of H are -neighbours if and only if and are neighbouring subsets of G. Use Exercise 19(d) to prove that satisfies condition (ii) in Exercise 18(c).)
(e) Let . Suppose is finite. Show that:
(Let T be a non-empty S-connected finite subset of G and T' (resp. T'') the set of ordered pairs of S-neighbouring elements whose first element (resp. both of whose elements) belongs (resp. belong) to T. and it should be shown by induction on that
Apply the result to , noting that is equipotent to .)
Solution
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