Bourbaki

Exercise 22, § 7

Algebra, I, 165

(a) Let (yn)n∈Z(y_n)_{n \in \mathbf{Z}} be a basic family of a group F. Let ϕ\phi be the automorphism of F which maps yny_n to yn+1y_{n+1}; this automorphism defines as operation τ\tau of Z\mathbf{Z} on F; let E=F×τZE = F \times_\tau \mathbf{Z} be the corresponding semi-direct product. Show that the elements x=(e,1)x = (e, 1) and y=(y0,0)y = (y_0, 0) form a basic family of E. (Let Fx,yF_{x, y} be the free group constructed on {x,y}\{x, y\} and let ff be the canonical homomorphism of Fx,yF_{x, y} into E. Show that there exists a homomorphism g:E→Fx,yg : E \to F_{x, y} such that g((0,1))=xg((0, 1)) = x and g((yn,0))=xnyx−ng((y_n, 0)) = x^n y x^{-n} and ff and gg are inverses of one another.)

(b) Deduce that the normal subgroup of Fx,yF_{x, y} generated by yy is a free group with basic family (xnyx−n)n∈Z(x^n y x^{-n})_{n \in \mathbf{Z}}. Obtain this result by applying Exercise 20 to the representative system consisting of the xn,n∈Zx^n, n \in \mathbf{Z}.

(c) Extend the above to free groups of arbitrary rank.

Solution

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