Bourbaki

Exercise 26, § 7

Algebra, I, 166

Let X be a set and g an element of the free group F(X)F(X). Let g=∏α=1nxαm(α)g = \prod_{\alpha=1}^n x_\alpha^{m(\alpha)} be the canonical decomposition of g as a product of powers of elements of X (cf. no. 5, Proposition 7). The integer l(g)=∑α∣m(α)∣l(g) = \sum_\alpha |m(\alpha)| is called the length of g. (a) g is called cyclically reduced if either x1≠xnx_1 \neq x_n or x1=xnx_1 = x_n and m(1)m(n)>0m(1)m(n) > 0. Show that every conjugacy class of F(X)F(X) contains one and only one cyclically reduced element; it is the element of minimum length of the class in question. (b) An element x∈F(X)x \in F(X) is called primitive if there does not exist an integer n≥2n \geq 2 and an element g∈F(X)g \in F(X) such that x=gnx = g^n. Show that every element z≠ez \neq e of F(X)F(X) can be written uniquely in the form xnx^n with n≥1n \geq 1 and x primitive. (Reduce it to the case where z is cyclically reduced and observe that, if z=xnz = x^n, the element x is also cyclically reduced.) Show that the centralizer of z is the same as that of x; it is the cyclic subgroup generated by x.

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