Bourbaki

Exercise 33, § 7

Algebra, I, 168

Let E=G∗AG′E = G *_A G' be the sum of two groups amalgamated by a common subgroup A. Let P (resp. P') be a subset of G (resp. G') satisfying condition (A) of no. 3.

Let nn be an integer ≥1\geq 1. Let LnL_n denote the set of x∈Ex \in E whose reduced decomposition is of length ≤2n−1\leq 2n - 1. Let MnM_n denote the set of x∈Ex \in E of the form ap1p1′p2p2′…pnpn′ap_1p'_1p_2p'_2 \ldots p_np'_n, with a∈A,pi∈P−{e},pi′∈P′−{e}a \in A, p_i \in P - \{e\}, p'_i \in P' - \{e\}; similarly, let Mn′M'_n denote the set of elements of the form ap1′p1p2′p2…pn′pnap'_1p_1p'_2p_2 \ldots p'_np_n, where a,pi,pi′a, p_i, p'_i satisfy the same conditions.

(a) Show that Ln,MnL_n, M_n and Mn′M'_n are disjoint and that their union is the set of elements of EE whose reduced decomposition is of length ≤2n\leq 2n.

(b) Construct a bijection ε\varepsilon of MnM_n onto Mn′M'_n such that ε(ax)=aε(x)\varepsilon(ax) = a\varepsilon(x) if a∈A,x∈Mna \in A, x \in M_n.

(c) Let Xn=Ln∪MnX_n = L_n \cup M_n and Xn′=Ln∪Mn′X'_n = L_n \cup M'_n; show that G.Xn=XnG.X_n = X_n and G′.Xn′=Xn′G'.X'_n = X'_n.

(d) ε\varepsilon extends to a bijection of XnX_n onto Xn′X'_n by setting ε(x)=x\varepsilon(x) = x if x∈Lnx \in L_n. Show that EE can operate on XnX_n so that g(x)=gxg(x) = gx if g∈G,x∈Xng \in G, x \in X_n and g′(x)=ε−1(g′∈(x))g'(x) = \varepsilon^{-1}(g' \in (x)) if g′∈G′,x∈Xng' \in G', x \in X_n. Show that, if g∈Xng \in X_n, then g(e)=gg(e) = g.

(e) Let τn:E→GXn\tau_n : E \to \mathscr{G}_{X_n} be the homomorphism defined by the action of EE on XnX_n described above and let RnR_n be the kernel of τn\tau_n. Show that Rn∩Xn={e}R_n \cap X_n = \{e\}; deduce that the intersection of the RnR_n reduces to ee.

(f) When GG and G′G' are finite, show that EE is residually finite (cf. § 5, Exercise 5). (Note that the RnR_n are then subgroups of finite index.)

Solution

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Transcribed from the printed volume. Not translated.