Exercise 38, § 7
Algebra, I, 170
Bourbaki marks this one as harder than the rest.
Let be a finite set, the free group constructed on and .
(a) Let be the set of products . Show that every connected -component (cf. Exercise 18) of contains one and only one element of the form with and for .
(b) Deduce from (a) a bijection of the set of ends of (cf. Exercise 37) onto the set of infinite sequences of elements of such that for all . In particular, the number of ends of is equal to if .
Solution
No solution has been written yet.